Chapter 2

11.

a) Mean is 2

b) Median can be 2

c) Sum of square deviations is 56.

d) Variance is installment payments on your 666 or perhaps 2 . several

e) Common deviation is usually 1 . 632 or 1 ) 6

12.

a) Indicate is 1312. 4 or perhaps 1312

b) Median is usually 1361

c) Sum of square deviations is 76092. 2

d) Variance can be 15218. 44

e) Common deviation is definitely 123. 363

13.

a) Mean can be 3. 166

b) Median is 3. 25

c) Sum of square deviations is 0. 44738

d) Variance is usually 0. 074

e) Regular deviation is 0. 272

16.

a) Governor-Mean is 43 and Common deviation can be 5. 916

CEO- Indicate is forty-four and regular deviation is 10. 954

b) In order to estimate the mean or average for the governors and CEO's, I actually added together all the characters and divided that quantity by 4 since you will find 4 quantities. Calculate the normal deviation by getting the typical of the average (mean) of the numbers. Hence the average of 43 pertaining to the governors is 5. 916 and the average of 44 intended for the CEO's is 12. 954. c) Judging from the results you observe that the CEO's have greater desks compared to the governors. The difference between mean and regular deviation is that mean is the sum in the scores divided by the volume of scores and standard deviation is the sq root of the typical of the square-shaped deviations in the mean. twenty one

Chapter a few

14.

a) unces (340) sama dengan (340-300)/20 = 40/20 = 2

b) z(310) = (310-300)/20 sama dengan 10/20 sama dengan. 5

c) z(260) sama dengan (260-300)/20 sama dengan -40/20 sama dengan -2

Natural Scores

d) z sama dengan 2 . four score = 300 + 20 by 2 . four = 300 +48 = 348

e) z = 1 . 5 score = 3000 + 20 times 1 . your five = three hundred + 31 = 330

f) z = zero, score sama dengan 300

g) z sama dengan -4. your five, score = 300 & 20 back button -4. 5 = 300 -90 sama dengan 210

12-15. z(81) = (81-50)/2 = 31/20 sama dengan 1 . 55, z(6. 4) = (6. 4-0)/5 = 1 . twenty eight. So , the verbal potential test is definitely higher. It is advisable to figure this kind of out by standardizing both equally scores by simply converting them to Z ratings. 22.

a) It's a non-random test because nonrandom samples will be limited since they are not as associated with the population you aren't studying since random selections are....